std::logical_and
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< cpp | utility | functional
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| Defined in header <functional>
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| template< class T > struct logical_and; |
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論理AND(論理積)を行うための関数オブジェクト。効率的に型operator&&上
T呼び出し.Original:
Function object for performing logical AND (logical conjunction). Effectively calls operator&& on type
T.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
目次 |
[編集] メンバータイプ
| タイプ
Original: Type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
result_type
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bool
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first_argument_type
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T
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second_argument_type
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T
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[編集] メンバ関数
| operator() |
論理積(AND)の二つの引数のを返します Original: returns the logical AND of the two arguments The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (パブリックメンバ関数) |
のstd :: logical_and ::Original:std::logical_and::The text has been machine-translated via Google Translate.
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Original:
std::logical_and::
The text has been machine-translated via Google Translate.
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| bool operator()( const T& lhs, const T& rhs ) const; |
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Returns the logical AND of lhs and rhs.
Parameters
| lhs, rhs | - | 論理積の計算するための値
Original: values to compute logical AND of The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Return value
The result of lhs && rhs.
Exceptions
(none)
Possible implementation
bool operator()(const T &lhs, const T &rhs) const { return lhs && rhs; } |