std::divides

 

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支援を入力します (basic types, RTTI, type traits)

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関係演算子 Original: Relational operators The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions.

rel_ops::operator!= rel_ops::operator> rel_ops::operator<= rel_ops::operator>=

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forward (C++11)

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関数オブジェクト

関数ラッパー Original: Function wrappers The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions.
function (C++11)
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オペレーターのラッパー Original: Operator wrappers The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions.
plus minus negate multiplies divides modulus logical_and logical_or logical_not	equal_to not_equal_to greater less greater_equal less_equal bit_and bit_or bit_xor
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binder1st binder2nd (廃止予定) (廃止予定)
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Defined in header <functional>
template< class T > struct divides;

除算を実行するための関数オブジェクト。効率的に型operator/の2つのインスタンスをT呼び出し.

Original:

Function object for performing division. Effectively calls operator/ on two instances of type T.

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メンバータイプ

タイプ Original: Type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions.	Definition
result_type	T
first_argument_type	T
second_argument_type	T

メンバ関数

operator()	第二引数で最初の引数を除算した結果を返します Original: returns the result of the division of the first argument by the second argument The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (パブリックメンバ関数)

stdは::分割::

Original:

std::divides::

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operator()

T operator()( const T& lhs, const T& rhs ) const;

Returns the result of division of lhs by rhs.

Parameters

lhs, rhs

-

他の値で1を除算する Original: values to divide one by other The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions.

Return value

The result of lhs / rhs.

Exceptions

(none)

Possible implementation

T operator()(const T &lhs, const T &rhs) const { return lhs / rhs; }