std::bit_xor
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< cpp | utility | functional
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| Defined in header <functional>
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| template< class T > struct bit_xor; |
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ビット単位の排他的論理和を計算するための関数オブジェクト。効率的に型operator^上
T呼び出し.Original:
Function object for performing bitwise XOR. Effectively calls operator^ on type
T.The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
目次 |
[編集] メンバータイプ
| タイプ
Original: Type The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Definition |
result_type
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T
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first_argument_type
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T
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second_argument_type
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T
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[編集] メンバ関数
| operator() |
二つの引数のビット単位のXORの結果を返します Original: returns the result of bitwise XOR of two arguments The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (パブリックメンバ関数) |
のstd :: BIT_XOR ::Original:std::bit_xor::The text has been machine-translated via Google Translate.
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Original:
std::bit_xor::
The text has been machine-translated via Google Translate.
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| T operator()( const T& lhs, const T& rhs ) const; |
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Returns the result of bitwise XOR of lhs and rhs.
Parameters
| lhs, rhs | - | 値のビットごとの排他的論理和を計算する
Original: values to compute bitwise XOR of The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
Return value
The result of lhs ^ rhs.
Exceptions
(none)
Possible implementation
T operator()(const T &lhs, const T &rhs) const { return lhs ^ rhs; } |