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std::is_lvalue_reference

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C++
 
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支援を入力します (basic types, RTTI, type traits)
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initializer_list(C++11)
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関係演算子
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支援を入力します
基本的なタイプ
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Basic types
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Type trait constants
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integral_constant(C++11)
 
Defined in header <type_traits>
template< class T >
struct is_lvalue_reference;
 (C + + 11以来)
Tは左辺値参照型である場合、メンバーが一定提供value等しいtrueを。その他のタイプのために、valuefalseです.
Original:
If T is an lvalue reference type, provides the member constant value equal true. For any other type, value is false.
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目次

Inherited from std::integral_constant

Member constants

value
[静的]
true T is an lvalue reference type もし、そうでなければfalse
Original:
true if T is an lvalue reference type , false otherwise
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(公共の静的メンバ定数)

Member functions

operator bool
boolにオブジェクトは、value返しに変換します
Original:
converts the object to bool, returns value
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(パブリックメンバ関数)

Member types

タイプ
Original:
Type
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 Definition
value_type bool
type std::integral_constant<bool, value>

[編集] 可能な実装

template<class T> struct is_lvalue_reference     : std::false_type {};
template<class T> struct is_lvalue_reference<T&> : std::true_type {};

[編集] 例

#include <iostream>
#include <type_traits>
 
class A {};
 
int main() 
{
    std::cout << std::boolalpha;
    std::cout << std::is_lvalue_reference<A>::value << '\n';
    std::cout << std::is_lvalue_reference<A&>::value << '\n';
    std::cout << std::is_lvalue_reference<A&&>::value << '\n';
    std::cout << std::is_lvalue_reference<int>::value << '\n';
    std::cout << std::is_lvalue_reference<int&>::value << '\n';
    std::cout << std::is_lvalue_reference<int&&>::value << '\n';
}

Output: 

false
true
false
false
true
false

[編集] も参照してください

(C++11)
タイプかどうかをチェックするには、どちらか左辺値参照や右辺値参照です
Original:
checks if a type is either lvalue reference or rvalue reference
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(クラステンプレート) [edit]
(C++11)
タイプかどうかをチェックするには、で右辺値参照
Original:
checks if a type is rvalue reference
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(クラステンプレート) [edit]
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