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std::is_compound

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C++
 
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支援を入力します (basic types, RTTI, type traits)
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日付と時刻
関数オブジェクト
initializer_list(C++11)
bitset
hash(C++11)
関係演算子
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Relational operators
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rel_ops::operator!=
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pair
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支援を入力します
基本的なタイプ
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Basic types
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基本的なタイプ
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Numeric limits
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numeric_limits
Cの数値は、インターフェイスを制限します
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Runtime type information
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Type traits
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is_compound(C++11)
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is_constructible
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is_nothrow_constructible		(C++11)
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is_copy_constructible
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is_assignable
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is_move_assignable
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is_destructible
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underlying_type(C++11)
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Type trait constants
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integral_constant(C++11)
 
Defined in header <type_traits>
template< class T >
struct is_compound;
 (C + + 11以来)
T複合型（つまり、任意のcv-修飾変異体を含む配列、関数、オブジェクトポインタ、関数ポインタ、メンバオブジェクトポインタ、メンバ関数ポインタ、参照、クラス、共用体、または列挙型）である場合は、会員が一定提供value等しいtrue。その他のタイプのために、valuefalseです.
Original:
If T is a compound type (that is, array, function, object pointer, function pointer, member object pointer, member function pointer, reference, class, union, or enumeration, including any cv-qualified variants), provides the member constant value equal true. For any other type, value is false.
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目次

Inherited from std::integral_constant

Member constants

value
[静的]
true T is a compound type もし、そうでなければfalse
Original:
true if T is a compound type , false otherwise
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(公共の静的メンバ定数)

Member functions

operator bool
boolにオブジェクトは、value返しに変換します
Original:
converts the object to bool, returns value
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(パブリックメンバ関数)

Member types

タイプ
Original:
Type
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 Definition
value_type bool
type std::integral_constant<bool, value>

[編集] ノート

化合物の種類は、基本型から構成されているタイプです。どのようなC + +の型のいずれかの基本的なまたは化合物である.
Original:
Compound types are the types that are constructed from fundamental types. Any C++ type is either fundamental or compound.
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[編集] 可能な実装

template< class T >
struct is_compound : std::integral_constant<bool, !std::is_fundamental<T>::value> {};

[編集] 例

#include <iostream>
#include <type_traits>
 
int main() {
    class cls {};
    std::cout << (std::is_compound<cls>::value
                     ? "T is compound"
                     : "T is not a compound") << '\n';
    std::cout << (std::is_compound<int>::value
                     ? "T is compound"
                     : "T is not a compound") << '\n';
}

Output: 

T is compound
T is not a compound

[編集] も参照してください

(C++11)
タイプかどうかをチェックするには、基本的なタイプです
Original:
checks if a type is fundamental type
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(クラステンプレート) [edit]
(C++11)
タイプかどうかをチェックするには、スカラー型である
Original:
checks if a type is scalar type
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(クラステンプレート) [edit]
(C++11)
タイプかどうかをチェックするには、オブジェクト·タイプです
Original:
checks if a type is object type
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(クラステンプレート) [edit]
(C++11)
タイプかどうかをチェックするには、配列型です
Original:
checks if a type is an array type
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(クラステンプレート) [edit]
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