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std::set_symmetric_difference

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< cpp‎ | algorithm

 
 
アルゴリズムライブラリ
機能します
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Functions
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シーケンス動作を非改変
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Non-modifying sequence operations
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シーケンス動作を変更する
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Modifying sequence operations
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操作を仕切る
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Partitioning operations
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(ソートされた範囲で)ソート操作
Original:
Sorting operations (on sorted ranges)
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バイナリ検索操作(ソート範囲で)
Original:
Binary search operations (on sorted ranges)
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(ソートされた範囲で)操作を設定します
Original:
Set operations (on sorted ranges)
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set_difference
set_intersection
set_symmetric_difference
set_union
ヒープ操作
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Heap operations
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最小値/最大値操作
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Minimum/maximum operations
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数値演算
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Numeric operations
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Cライブラリ
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C library
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Defined in header <algorithm>
template< class InputIt1, class InputIt2, class OutputIt >

OutputIt set_symmetric_difference( InputIt1 first1, InputIt1 last1,
                                   InputIt2 first2, InputIt2 last2,

                                   OutputIt d_first );
(1)
template< class InputIt1, class InputIt2,

          class OutputIt, class Compare >
OutputIt set_symmetric_difference( InputIt1 first1, InputIt1 last1,
                                   InputIt2 first2, InputIt2 last2,

                                   OutputIt d_first, Compare comp );
(2)
ソート範囲[first1, last1)[first2, last2)でレンジ先頭にソートされた範囲[first2, last2)で発見されていない[first1, last1)ソート範囲の要素で発見されていないソート範囲d_firstから要素がコピーされます。結果として得られる範囲は、またソートされます。最初のバージョンでは、両方の入力がoperator<でソートされている範囲では、2番目のバージョンは、それらが与えられた比較関数compでソートされることを想定して期待しています。いくつかの要素がm[first1, last1)n[first2, last2)倍であることが判明した場合、それは正確にd_firststd::abs(m-n)倍にコピーされます。 m>n場合は、それらの要素の最後m-n[first1,last1)からコピーされ、そうでなければ最後n-m要素が[first2,last2)からコピーされます。結果の範囲は入力レンジのいずれかと重複することはできません.
Original:
Copies the elements from the sorted range [first1, last1) which are not found in the sorted range [first2, last2) and the elements from the sorted range [first2, last2) which are not found in the sorted range [first1, last1) to the range beginning at d_first. The resulting range is also sorted. The first version expects both input ranges to be sorted with operator<, the second version expects them to be sorted with the given comparison function comp. If some element is found m times in [first1, last1) and n times in [first2, last2), it will be copied to d_first exactly std::abs(m-n) times. If m>n, then the last m-n of those elements are copied from [first1,last1), otherwise the last n-m elements are copied from [first2,last2). The resulting range cannot overlap with either of the input ranges.
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目次

[編集] パラメータ

first1, last1 -
要素の最初のソート範囲
Original:
the first sorted range of elements
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first2, last2 -
要素の第二ソート範囲
Original:
the second sorted range of elements
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comp - 比較関数. 最初の値が二つ目の値より小さい 場合、 ​trueを返します.

比較関数のシグネチャは以下と同等でなければなりません.

 bool cmp(const Type1 &a, const Type2 &b);

シグネチャはconstを含まなくても構いませんが, 比較関数は渡されたオブジェクトを変更してはなりません.
The types Type1 and Type2 must be such that objects of types InputIt1 and InputIt2 can be dereferenced and then implicitly converted to Type1 and Type2 respectively. ​

型の要件
-
InputIt1InputIterator

の要求を満足しなければなりません。

-
InputIt2InputIterator

の要求を満足しなければなりません。

-
OutputItOutputIterator

の要求を満足しなければなりません。

[編集] 値を返します

構築範囲の終わり過去イテレータ.
Original:
Iterator past the end of the constructed range.
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[編集] 複雑

最も2·(N1+N2-1)の比較で、どこN1= std::distance(first1, last1)N2= std::distance(first2, last2).
Original:
At most 2·(N1+N2-1) comparisons, where N1 = std::distance(first1, last1) and N2 = std::distance(first2, last2).
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[編集] 可能な実装

First version
template<class InputIt1, class InputIt2, class OutputIt>
OutputIt set_difference(InputIt1 first1, InputIt1 last1,
                        InputIt2 first2, InputIt2 last2,
                        OutputIt d_first)
{
    while (first1 != last1) {
        if (first2 == last2) return std::copy(first1, last1, d_first);
 
        if (*first1 < *first2) {
            *d_first++ = *first1++;
        } else {
            if (*first2 < *first1) {
                *d_first++ = *first2;
            } else {
                ++first1;
            }
            ++first2;
        }
    }
    return std::copy(first2, last2, d_first);
}
Second version
template<class InputIt1, class InputIt2,
         class OutputIt, class Compare>
OutputIt set_difference(InputIt1 first1, InputIt1 last1,
                        InputIt2 first2, InputIt2 last2,
                        OutputIt d_first, Compare comp)
{
    while (first1 != last1) {
        if (first2 == last2) return std::copy(first1, last1, d_first);
 
        if (comp(*first1, *first2)) {
            *d_first++ = *first1++;
        } else {
            if (comp(*first2, *first1)) {
                *d_first++ = *first2;
            } else {
                ++first1;
            }
            ++first2;
        }
    }
    return std::copy(first2, last2, d_first);
}

[編集]

#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>
int main()
{
    std::vector<int> v1{1,2,3,4,5,6,7,8     };
    std::vector<int> v2{        5,  7,  9,10};
    std::sort(v1.begin(), v1.end());
    std::sort(v2.begin(), v2.end());
 
    std::vector<int> v_intersection;
 
    std::set_symmetric_difference(
        v1.begin(), v1.end(),
        v2.begin(), v2.end(),
        std::back_inserter(v_intersection));
 
    for(int n : v_intersection)
        std::cout << n << ' ';
}

出力:

1 2 3 4 6 8 9 10

[編集] も参照してください

1セットが他のサブセットである場合はtrueを返します
Original:
returns true if one set is a subset of another
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(関数テンプレート) [edit]
2つの集合の差分を計算します
(関数テンプレート) [edit]
2つの集合の和を計算します。
(関数テンプレート) [edit]
2つの集合の積を計算します
(関数テンプレート) [edit]