std::find_end
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| Defined in header <algorithm>
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| template< class ForwardIt1, class ForwardIt2 > ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, |
(1) | |
| template< class ForwardIt1, class ForwardIt2, class BinaryPredicate > ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, |
(2) | |
[s_first, s_last)範囲[first, last)インチ最初のバージョンは、要素を比較するoperator==使用して、2番目のバージョンは、指定されたバイナリ述語pを使用しています. [s_first, s_last) in the range [first, last). The first version uses operator== to compare the elements, the second version uses the given binary predicate p. You can help to correct and verify the translation. Click here for instructions.
目次 |
[編集] パラメータ
| first, last | - | 検討する要素の範囲
Original: the range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
| s_first, s_last | - | 検索する要素の範囲
Original: the range of elements to search for The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. | |||||||||
| p | - | binary predicate which returns true if the elements should be treated as equal. The signature of the predicate function should be equivalent to the following:
The signature does not need to have const &, but the function must not modify the objects passed to it. | |||||||||
| Type requirements | |||||||||||
-ForwardIt1 must meet the requirements of ForwardIterator.
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-ForwardIt2 must meet the requirements of ForwardIterator.
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[編集] 値を返します
[s_first, s_last)の先頭を指すイテレータ[first, last).[s_first, s_last) in range [first, last).You can help to correct and verify the translation. Click here for instructions.
lastが返されます。 (C + + 11時まで)last is returned. (C + + 11時まで)You can help to correct and verify the translation. Click here for instructions.
[s_first, s_last)が空であるか、そのような部分列が見つからない場合は、lastが返されます。場合(C + + 11以来)[s_first, s_last) is empty or if no such subsequence is found, last is returned. (C + + 11以来)You can help to correct and verify the translation. Click here for instructions.
[編集] 複雑
S*(N-S+1)の比較ではどこS = distance(s_first, s_last)とN = distance(first, last).S*(N-S+1) comparisons where S = distance(s_first, s_last) and N = distance(first, last).You can help to correct and verify the translation. Click here for instructions.
[編集] 可能な実装
| First version |
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template<class ForwardIt1, class ForwardIt2> ForwardIt1 find_end(ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last) { if (s_first == s_last) return last; ForwardIt1 result = last; while (1) { ForwardIt1 new_result = std::search(first, last, s_first, s_last); if (new_result == last) { return result; } else { result = new_result; first = result; ++first; } } return result; } |
| Second version |
template<class ForwardIt1, class ForwardIt2, class BinaryPredicate> ForwardIt1 find_end(ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p) { if (s_first == s_last) return last; ForwardIt1 result = last; while (1) { ForwardIt1 new_result = std::search(first, last, s_first, s_last, p); if (new_result == last) { return result; } else { result = new_result; first = result; ++first; } } return result; } |
[編集] 例
find_end().
find_end() to search for two different sequences of numbers.
You can help to correct and verify the translation. Click here for instructions.
#include <algorithm> #include <iostream> #include <vector> int main() { std::vector<int> v{1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4}; std::vector<int>::iterator result; std::vector<int> t1{1, 2, 3}; result = std::find_end(v.begin(), v.end(), t1.begin(), t1.end()); if (result == v.end()) { std::cout << "subsequence not found\n"; } else { std::cout << "last subsequence is at: " << std::distance(v.begin(), result) << "\n"; } std::vector<int> t2{4, 5, 6}; result = std::find_end(v.begin(), v.end(), t2.begin(), t2.end()); if (result == v.end()) { std::cout << "subsequence not found\n"; } else { std::cout << "last subsequence is at: " << std::distance(v.begin(), result) << "\n"; } }
Output:
last subsequence is at: 8 subsequence not found
[編集] も参照してください
| 互いに隣接する2つの同一の(またはいくつかの他の関係)のアイテムを見つけることができます Original: finds two identical (or some other relationship) items adjacent to each other The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (関数テンプレート) | |
| (C++11) |
特定の条件を満たす最初の要素を検索します Original: finds the first element satisfying specific criteria The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (関数テンプレート) |
| searches for any one of a set of elements (関数テンプレート) | |
| 範囲内の要素の数は連続したコピーを検索します Original: searches for a number consecutive copies of an element in a range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (関数テンプレート) | |